Question

Помогите с математикой
Пределы

Answer 1

$limlimits_{ntoinfty}dfrac{6n^3-sqrt{n^5+1}}{sqrt{4n^6+3}-n}=limlimits_{ntoinfty}dfrac{6-sqrt{dfrac{1}{n}+dfrac{1}{n^6}}}{sqrt{4+dfrac{3}{n^6}}-dfrac{1}{n^2}}=dfrac{6}{sqrt 4}=3$