Question

4arccos(-√2/2)-3arccos1+2arcsin1/2-arctg√3/3
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Answer 1

Ответ:

19π/6.

Пошаговое объяснение:

4arccos(-√2/2) - 3arccos1 + 2arcsin1/2 - arctg√3/3 = 4•(π - arccos√2/2) - 3•0 + 2•π/6 - π/6 = 4•(π - π/4) - 0 + 2π/6 - π/6 = 3π + π/6 = 3 1/6•π или 19π/6.