Question

Решите системы неравенств:
а) 3x+9>0,
x-5<1;
б) 2-у >= 3,
3y-1<=2.

Answer 1

$1)left { {{3x+9>0} atop {x-5<1}} right.\\left { {{3x>-9} atop {x<6}} right.\\left { {{x>-3} atop {x<6}} right. \\Otvet:boxedxin(-3;6)$

$2)left { {{2-ygeq3 } atop {3y-1leq2 }} right.\\left { {{-ygeq1 } atop {3yleq3}} right.\\left { {{yleq-1 } atop {yleq 1}} right.Rightarrow yleq-1\\Otvet:boxedxin(-infty;-1]$