Question

Решите уравнение пожалуйста

Answer 1

$ttdisplaystyle 1) ; dfrac{dfrac{1}{6}}{dfrac{1}{4} x - dfrac{1}{3}} - dfrac{3}{8} = dfrac{1}{40} \\ dfrac{1}{6} : (dfrac{1}{4} x - dfrac{1}{3}) = dfrac{1}{40} + dfrac{3}{8} \\ dfrac{1}{6} : (dfrac{3}{12} x - dfrac{4}{12}) = dfrac{1+15}{40} \\ dfrac{1}{6} : dfrac{3x-4}{12} = dfrac{16}{40} \\ dfrac{1}{6}cdot dfrac{12}{3x-4} = dfrac{2}{5} \\ dfrac{2}{3x-4} = 0,4 \\ 2 : (3x - 4) = 0,4 \ 3x - 4 = 2 : 0,4 \ 3x - 4 = 5 \ 3x = 5 + 4 \ 3x = 9 \ x = 9 : 3 \ x = 3 \\\ 2) ; dfrac{dfrac{1}{4}}{dfrac{3}{4} x - dfrac{1}{2}} + dfrac{2}{5} = dfrac{1}{2} \\ (dfrac{1}{4} : (dfrac{3}{4} x - dfrac{1}{2})) = dfrac{1}{2} - dfrac{2}{5} \\ (dfrac{1}{4} : (dfrac{3}{4} x = dfrac{2}{4})) = dfrac{5-4}{10} \\ dfrac{1}{4} : dfrac{3x-2}{4} = dfrac{1}{10} \\ dfrac{1}{4}cdot dfrac{4}{3x-2} = dfrac{1}{10} \\ dfrac{1}{3x-2} = dfrac{1}{10} \\3x-2 = 10 \3x = 10+2 \ 3x = 12 \ x = 12 : 3 \ x = 4$