Question

Разложить на множетели
x3-x2y-x+y

Answer 1

$x^3-x^2y-x+y=x^2(x-y)-(x-y)=(x-y)(x^2-1)=\\=(x-y)(x-1)(x+1)$

Answer 2

$displaystyle tt x^3-x^2y-x+y=x^2(x-y)-(x-y)=(x-y)(x^2-1)=bold{(x-y)(x-1)(x+1)}$

Ответ: $displaystyle tt (x-y)(x-1)(x+1)$