Question

Найти tgα ,если: 4sinα+3cosα/3sinα - 16cosα=2

Answer 1

$frac{4sinalpha+3cosalpha }{3sinalpha -16cosalpha } =2\\4sinalpha +3cosalpha=2cdot (3sinalpha -16cosalpha )\\4sinalpha +3cosalpha=6sinalpha -32cosalpha \\4sinalpha -6sinalpha =-3cosalpha -32cosalpha \\-2sinalpha =-35cosalpha \\ tgalpha =frac{(-35)}{(-2)}=17,5$