Question

Найти корни уравнения: z2+10z+16=0

Answer 1

$z^{2} +10z+16=0\D=b^{2}-4ac= 10^{2} -4*1*16=36\x= frac{-b-sqrt{D} }{2a}=frac{-10-6}{2}=-frac{16}{2}=-8 \x= frac{-b+sqrt{D} }{2a}=frac{-10+6}{2}=-frac{4}{2}=-2$