Question

{sinx•siny-cosx•cosy= -1
{sinx•cosy-cosx•siny=1/2
Решить систему уравнений
50 балов!!!

Answer 1

Ответ:

Объяснение:

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Answer 2

sin(x-y)=1/2

-cos(x+y)=-1

$si(x - y) = frac{1}{2} \ (x - y) = {( - 1)}^{k} arcsin frac{1}{2} + pi : k \ x - y = {( - 1)}^{k} frac{pi}{6} + pi : k$

$- cos(x + y) = - 1 \ cos(x + y) = 1 \ x + y = 2pi : n$

$x - y = {( - 1)}^{k} frac{pi}{6} + pi : k \ x + y = 2pi : n \ 2x = {( - 1)}^{k} frac{pi}{6} + pi : k + 2pi : n \ x = {( - 1)}^{k} frac{pi}{12} + frac{pi}{2} : k + pi : n \ y = 2pi : n - x = \ = 2pi : n - {( - 1)}^{k} frac{pi}{12} + frac{pi}{2} : k + pi : n = \ = - {( - 1)}^{k} frac{pi}{12} + frac{pi}{2} : k + 3pi : n$