Question

Срочно!!! Пожалуйста

Answer 1

$1); ; frac{x+3}{5}-frac{x^2-4}{8}leq1; Big |cdot 40\\8(x+3)-5(x^2-4)leq 40\\8x+24-5x^2+20leq 40\\5x^2-8x-4leq 0\\D/4=4^2+20=36; ,; ; x_1=frac{4-6}{5}=-0,4; ; ,; ; x_2=frac{4+6}{5}=2\\5(x+0,4)(x-2)leq 0\\znaki:; ; +++[-0,4; ]---[; 2; ]+++\\xin [-0,4; ;; 2; ]$

$2); ; frac{3x^2-11}{8}<10-frac{37-x^2}{6}; Big|cdot 24\\3(3x^2-11)<240-4, (37-x^2)\\9x^2-33<240-148+4x^2\\5x^2-125<0\\5(x^2-25)<0\\5(x-5)(x+5)<0\\znaki:; ; +++(-5)---(5)+++\\xin (-5;5)$