Question

1)(2,6:(-13)+1,2):(-0,1);
2)7/8:(-2 1/4):5/6:(2 1/2):(-6/25);
3) (4 3/7)•1 4/31+(-6 2/3):3 1/3;​

Answer 1

1)

$displaystyle tt (2,6div(-13)+1,2)div(-0,1)=(-0,2+1,2)div(-0,1)=1div(-0,1)=-10$

2)

$displaystyle tt frac{7}{8}div(-2frac{1}{4})divfrac{5}{6}div(2frac{1}{2})div(-frac{6}{25})=frac{7}{8}div(-frac{9}{4})divfrac{5}{6}divfrac{5}{2}div(-frac{6}{25})=\\\ =frac{7}{8}cdotfrac{4}{9}cdotfrac{6}{5}cdotfrac{2}{5}cdotfrac{25}{6}=frac{7}{2}cdotfrac{1}{9}cdotfrac{2}{5}cdot5=7cdotfrac{1}{9}=frac{7}{9}$

3)

$displaystyle tt (4frac{3}{7})cdot1frac{4}{31}+(-6frac{2}{3})div3frac{1}{3}=frac{31}{7}cdotfrac{35}{31}+(-frac{20}{3})divfrac{10}{3}=frac{5}{1}+(-frac{20}{3})cdotfrac{3}{10}=\\\=5+(-frac{2}{1})==5-2=3$