Question

решите уравнение (3x+4)²-(3x-1)(3x+1)=41​

Answer 1

Ответ:

$(3x + 4) {}^{2} - (3x - 1)(3x + 1) = 41 \ 9x {}^{2} + 24x + 16 - (9x {}^{2} - 1) = 41 \ 9x {}^{2} + 24x + 16 - 9x {}^{2} + 1 = 41 \ 24x + 17 = 41 \ 24x = 41 - 17 \ 24x = 24 \ x = 1$

Answer 2

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Answer 3

Ответ:

(3x+4)*2-(3x-1) (3x+1) =41

9x*2+24x+16-(9x*2-1) =41

24x=41-17

24x=24

X=1

Объяснение: