Question

Решите, пожалуйста!
(3-_/10)х>19-6_/10

Answer 1

$(3-sqrt{10})x>19-6sqrt{10}\\x<frac{19-6sqrt{10}}{3-sqrt{10}}\\xin Big(-infty ,frac{19-6sqrt{10}}{3-sqrt{10}}; Big )\\\\P.S.; ; (3-sqrt{10})x>18-6sqrt{10}\\(3-sqrt{10}), x>6cdot (3-sqrt{10})\\x<frac{6, (3-sqrt{10})}{3-sqrt{10}}\\x<6\\xin (-infty ;6,)$

$star ; ; (3-sqrt{10})<0; ; ,; ; sqrt{10}approx 3,16; ; star$