Question

РЕШИТЕ ПО ФИЗИКЕ! ПЖ 25 БАЛОВ.​ только с решением

Answer 1

Ответ:

Объяснение:

$R = dfrac{R_1R_2}{R_1+R_2} + R_3 + dfrac{R_4R_5}{R_4+R_5} = dfrac{2*3}{2+3} + 0.8 + dfrac{4*4}{4+4} = 4~Om$

$I_{sum} = dfrac{U}{R} = dfrac{4}{4} = 1A\I_{12} = I = 1A\U_1 = U_2 = U_{12} = I_{12}*dfrac{R_1R_2}{R_1+R_2} = 1*1.2 = 1.2~V\I_1 = dfrac{U_1}{R_1} = dfrac{1.2}{2} = 0.6~A\I_2 = dfrac{U_2}{R_2} = dfrac{1.2}{3} = 0.4~A\I_3 = I = 1~A\U_3 = I_3*R_3 = 1*0.8 = 0.8~V\I_{45} = I = 1A\U_4 = U_5 = U_{45} = I_{45}*dfrac{R_4R_5}{R_4+R_5} = 1*2 = 2~V\I_4 = dfrac{U_4}{R_4} = dfrac{2}{4} = 0.5~A\I_5 = dfrac{U_5}{R_5} = dfrac{2}{4} = 0.5~A$