Question

2х^2+2х=5 через дискриминант​

Answer 1

Ответ:

Объяснение:

$2x^2+2x=5\2x^2+2x-5=0\D=4-4*2*(-5)=44\\x_1=frac{-2+2sqrt{11} }{4} =1.15831\x_2=frac{-2-2sqrt{11} }{4} =-2.15831$

Answer 2

$2x^{2} +2x=5\\2x^{2}+2x-5=0\\D=2^{2}-4*2*(-5)=4+40=44=(2sqrt{11})^{2}\\x_{1}=frac{-2-2sqrt{11}}{4}=-frac{1+sqrt{11}}{2}\\x_{2}=frac{-2+2sqrt{11}}{4}=frac{sqrt{11}-1}{2}$