Question

Даю 18 баллов

Помогите с 3(в) 1 вариант

Answer 1

y’(x)=(1+cos(x))’(1-cos(x))-(1+cos(x))*(1-cos(x))’/ (1-cos(x))²=(-sin(x)(1-cos(x))-sin(x)(1+cos(x)))/(1-cos(x))²=(-sin(x)+sin(x)cos(x)-sin(x)-sin(x)cos(x))/(1-cos(x))²= -2sin(x)/(1-cos(x))²

y’(π/4)= -2sin(π/4)/(1-cos(π/4))²=-2*√2/2/ (1-√2/2)²= -√2/(1-√2+0,5)= √2/(√2-1,5)