Question

30 БАЛЛОВ!!!!!Помогите решить пожалуйста,математика,6 класс.

Answer 1

Ответ:

▪︎1

$frac{52}{45} - (3 frac{3}{5} - 1 frac{7}{9} ) times ( frac{1}{2} - frac{1}{3} ) = frac{52}{45} -2 frac{27 - 35}{45} times frac{3 - 2}{6} = frac{52}{45} - 1 frac{37}{45} times frac{1}{6} = frac{52}{45} - frac{82}{45 times 6} = 1 frac{7}{45} - frac{41}{135} = 1 frac{21 - 41}{135} = 1 - frac{20}{135} = 1 - frac{4}{27} = frac{23}{27}$

▪︎2

$(3 frac{8}{60} - 2 frac{5}{24} ) div 9 frac{1}{4} div 0.1 = 1 frac{16 - 25}{120} div frac{37}{4} div frac{1}{10} = frac{37}{40} times frac{4}{37} times 10 = 1$

▪︎3

$(5.625 times 1 frac{1}{3} - 3 frac{11}{18} div frac{5}{9} ) div 1 frac{2}{3} = (frac{45}{8} times frac{4}{3} - frac{65 times 9}{18 times 5} ) div frac{5}{3} = ( frac{15}{2} - frac{13}{2} ) times frac{3}{5} = 1 times frac{3}{5} = frac{3}{5}$

▪︎4

$frac{9}{10} + frac{4}{9} div (2 - 1 frac{11}{21} ) - 1 frac{2}{3} = frac{9}{10} + frac{4}{9} div frac{21 - 11}{21} - 1 frac{2}{3} = frac{9}{10} + frac{4 times 21}{9 times 10} - 1 frac{2}{3} = frac{9}{10} + frac{2 times 7}{3 times 5} - 1 frac{2}{3} = frac{27 + 28}{30} - 1 frac{20}{30} = frac{55}{30} - 1 frac{20}{30} = 1frac{15}{30} - 1 frac{20}{30} = frac{5}{30} =frac{1}{6}$

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