Question

2x²-х-1=х²-5х-(-1-х²)
Помогите пожалуйста, дам 35 баллов!

Answer 1

$2 {x}^{2} - x - 1 = {x}^{2} - 5x - ( - 1 - {x}^{2} ) \ 2 {x}^{2} - x - 1 - {x}^{2} + 5x = 1 + {x}^{2} \ 2 {x}^{2} + 4x - 1 - 2 {x}^{2} - 1 = 0 \ 4x - 2 = 0 \ 2x - 1 = 0 \ x = 0.5$