Question

8х^2-5х-3=0 пплииииззз​

Answer 1

Ответ:

x1 = 1; x2 = -3/8

Пошаговое объяснение:

D = b^2-4ac

D = (-5)^2-4*8*(-3) = 25+96 = 121

$sqrt{D} = sqrt{121} = 11$

x1 = (-b+$sqrt{D}$)/2a = (5+11)/16 = 16/16 = 1

x2 = (-b-$sqrt{D}$)/2a = (5-11)/16 = -6/16 = -3/8

Answer 2

$displaystyle tt 8x^{2} -5x-3=0$

$displaystyle tt D=b^{2}-4ac=(-5)^2-4*8*(-3)=121$

$displaystyle tt x=frac{-b-sqrt{D} }{2a}=frac{5-11}{2*8}=-frac{6}{16}=bold-frac{bold3}{bold8}$

$displaystyle tt x=frac{-b+sqrt{D} }{2a}=frac{5+11}{2*8}=frac{16}{16}=boldbold1$