Question

Найдите производную функции
y=x^2-3/x+2

Answer 1

$y=frac{x^2-3}{x+2}\\y'=frac{2x, (x+2)-(x^2-3)}{(x+2)^2}=frac{x^2+4x+3}{(x+2)^2}=frac{(x+1)(x+3)}{(x+2)^2}$