Question

Логарифмическое неравенство 3

Answer 1

$log_{frac{1}{2} }log_{3}(1-x)>log_{frac{1}{2} }2$

$left { {log_{3}(1-x)>0} atop {log_{3}(1-x)<2}} right. left {{1-x>0} atop { {log_{3}(1-x)>log_{3}1} atop {log_{3}(1-x)<log_{3}9}} right. left { {{1-x>1} atop {1-x<9}} right. left { {{x<0} atop {x>-8}} right.$

О т в е т. (-8;0)