Question

решите уравнение:(x-2)^3=|x+6|^2-44​

Answer 1

$displaystyle tt (x-2)^3=|x+6|^2-44\displaystyle tt x^3-6x^2+12x-8=(x+6)^2-44\displaystyle tt x^3-6x^2+12x-8=x^2+12x+36-44\displaystyle tt x^3-6x^2-8=x^2+36-44\displaystyle tt x^3-6x^2-8=x^2-8\displaystyle tt x^3-6x^2=x^2\displaystyle tt x^3-6x^2-x^2=0\displaystyle tt x^3-7x^2=0\displaystyle tt x^2(x-7)=0\displaystyle tt bold{x_1=0}\displaystyle tt x-7=0\displaystyle tt bold{x_2=7}$