Question

x^2+5x-4=0 pleaseee​

Answer 1

x²+5x-4=0

Ищем по дискриминанту:

D = b² - 4*a*c

D = 5² - 4 *1 * (-4) = 25 + 16 = 41

$x1.2 = frac{ - b + - sqrt{D} }{2a}$

[tex]x1 = frac{-5 + sqrt{41} }{2}

[tex]x2 = frac{-5 - sqrt{41} }{2}

Answer 2

Ответ:

Пошаговое объяснение:

$[begin{gathered}{x^2}+5x-4=0 hfill \D={b^2}-4ac={5^2}-4cdot 1cdot (-4)=25+16=41 hfill \{x_{1;2}}=frac{{-bpm sqrt D }}{{2a}}=frac{{-5pm sqrt {41}}}{{2cdot 1}} = frac{{-5pmsqrt {41} }}{2} hfill \{x_1}=frac{{-5+sqrt {41} }}{2} hfill \{x_2}=frac{{-5-sqrt {41} }}{2} hfill \ end{gathered} ]$