Question

Help please help me

Answer 1

a)
n(C12H22O11) = m/M = 100g/342 = 0,29 моль
(М = 12×12 + 22×1 + 16×11 = 342)
N = 6,02•10²³(Постоянная Авогадро) × 0,29 = 1,7458•10²³
b)
n(NaCl) = m/M = 150g/58,5 = 2, 56 моль
(M = 23 + 35,5 = 58,5)
N = 6,02•10²³ × 2,56 = 15,4112•10²³