Question

Решите уравнение 2/3|5x-4|+8,6=10

Answer 1

$displaystyle tt frac{2}{3}cdot|5x-4|+8,6=10\\ displaystyle tt frac{2}{3}cdot|5x-4|+frac{43}{5}=10:::::bigg|cdot15\\ displaystyle tt 10cdot|5x-4|+129=150\displaystyle tt 10cdot|5x-4|=150-129\ displaystyle tt 10cdot|5x-4|=21\displaystyle tt |5x-4|=21div10\ displaystyle tt |5x-4|=2,1\\ displaystyle tt 5x-4=2,1\displaystyle tt 5x=2,1+4\displaystyle tt 5x=6,1\displaystyle tt x=6,1div5\displaystyle tt bold{x_1=1,22}$

$displaystyle tt 5x-4=-2,1\displaystyle tt 5x=-2,1+4\displaystyle tt 5x=1,9\displaystyle tt x=1,9div5\displaystyle tt bold{x_2=0,38}$