Question

ctg240° +tg300° – sin(-225°) - cos 495°.​

Answer 1

Ответ:

Объяснение:

ctg240°+tg300°-sin(-225°)-cos 495°=

=ctg(180°+60°)+tg(360°-60°)-(-sin(180°+45°)-cos(360°-495°)=

=ctg60°-tg60°-sin45°-cos(-135°)=(√3/3)-√3-(√2/2)-(cos(180°-45°)=

=(-2√3/3)-(√2/2)+(√2/2)=-2√3/3.