Question

Решите уравнение:
3/4|6х-3|+9,2=11
Даю 30 баллов!

Answer 1

$displaystyle tt frac{3}{4}cdot|6x-3|+9,2=11\\ displaystyle tt frac{3}{4}cdot|6x-3|+frac{46}{5}=11:::::bigg|cdot20\\ displaystyle tt 15cdot|6x-3|+184=220\\ displaystyle tt 15cdot|6x-3|=220-184\\ displaystyle tt 15cdot|6x-3|=36:::::bigg|div15\\ displaystyle tt |6x-3|=frac{12}{5}$

$displaystyle tt 6x-3=frac{12}{5} : : : : : bigg| cdot5\\ displaystyle tt 5(6x-3)=12\\ displaystyle tt 30x-15=12\\ displaystyle tt 30x=12+15\\ displaystyle tt 30x=27\\ displaystyle tt x=27div30\\ displaystyle tt boxed{bold{x_1=0,9}}$

$displaystyle tt 6x-3=-frac{12}{5}:::::bigg|div5\\ displaystyle tt 5(6x-3)=-12\\ displaystyle tt 30x-15=-12\\displaystyle tt 30x=-12+15\\ displaystyle tt 30x=3\\ displaystyle tt x=3div30\\ displaystyle tt boxed{bold{x_2=0,1}}$