Question

(5-3y)-(4-2y)=y-8-(y-1)

Answer 1

Решение:

5-3у-4+2у=у-8-у+1

1-у= - 7

-у= - 7-1

-у= - 8

Ответ:

У=8

Answer 2

$displaystyle tt (5-3y)-(4-2y)=y-8-(y-1)\displaystyle tt 5-3y-4+2y=y-8-y+1\displaystyle tt 1-y=-7\displaystyle tt -y=-7-1\displaystyle tt -y=-8\displaystyle tt bold{y=8}$