Question

решите уравнение
(x-2)(x+3)=-2

Answer 1

$displaystyle tt (x-2)(x+3)=-2\displaystyle tt x^2+3x-2x-6=-2\displaystyle tt x^2+x-6-2=0\displaystyle tt x^2+x-4=0\displaystyle tt D=1^2-4cdot1cdot(-4)=1+16=17\displaystyle tt sqrt{D}=sqrt{17}\\ displaystyle tt bold{x_1}=frac{-1+sqrt{17}}{2}\\ displaystyle tt bold{x_2}=frac{-1-sqrt{17}}{2}$