Question

Помогите сделать 14 номер​

Answer 1

Объяснение:

$begin{array}{l}mathrm{5CH_{3}-CH_{2}-overset{+1}{C}HO + 2Koverset{+7}{Mn}O_{4} + 3H_{2}SO_{4} =} \ mathrm{= 5CH_{3}-CH_{2}-overset{+3}{C}OOH + 2overset{+2}{Mn}SO_{4} + K_{2}SO_{4} + 3H_{2}O}end{array} \\\left.begin{array}{r}mathrm{C^{+1} -2e^{-} to C^{+3}} \mathrm{Mn^{+7} +5e^{-} to Mn^{+2}}end{array}right|10left|begin{array}{l}mathrm{5 - reducing;agent} \mathrm{2 - oxidizing;agent}end{array}right.$

P.S. reducing agent - восстановитель

oxidizing agent - окислитель