Question

решить уравнение:
$2x^2-5x-3=0$

Answer 1

$displaystyle tt 2x^2-5x-3=0\\ displaystyle tt D=(-5)^2-4cdot2cdot(-3)=25+24=49\\ displaystyle tt sqrt{D}=sqrt{49}=7\\ displaystyle tt x_1=frac{5+7}{2cdot2}=frac{12}{4}=3\\displaystyle tt x_2=frac{5-7}{2cdot2}=frac{-2}{4}=-frac{1}{2}=-0,5$

Answer 2

$2 {x}^{2} - 5x - 3 = 0 \ D = 25 - 4 times 2 times ( - 3) = 25 + 24 = 49 = {7}^{2} \ x_1 = frac{5 + 7}{4} = frac{12}{4} = 3 \ x_2= frac{5 - 7}{4} = frac{ - 2}{4} = - 0.5$