Question

Доказать тождество.

Answer 1

$Abackslash(Acap B )={x|(xin A)bigwedge (xnotin (Acap B ))}={x|(xin A)bigwedge (xin (overline{A}cup overline{B}) )}={x|(xin A)bigwedge ((xin overline{A}) bigvee (xin overline{B}) )}={x|(xin o)bigvee ((xin A) bigwedge (xin overline{B}) )}={x|(xin A) bigwedge (xin overline{B}) }=Abackslash B$