Question

Как решить:
-0,6y*(-0,9)
-8а*2,5b
-5х*(-0,8y)*0,4z
9/28а * 7/18*(-b)
2 5/8х*(-16/63y)

Answer 1

$displaystyle tt -0,6ycdot(-0,9)=0,54y\\ displaystyle tt -8acdot2,5b=-20ab\\ displaystyle tt -5xcdot(-0,8y)cdot0,4z=-1,6xyz\\ displaystyle tt frac{9}{28}acdotfrac{7}{18}cdot(-b)=-frac{1}{4}acdotfrac{1}{2}b=-frac{1}{8}ab=-0,125ab\\ displaystyle tt 2frac{5}{8}xcdotbigg(-frac{16}{63}ybigg)=frac{21}{8}xcdotbigg(-frac{16}{63}ybigg)=-xcdotfrac{2}{3}y=frac{2}{3}xy$

Answer 2

Спасибо огромное)