Question

Найдите tg α и ctg α, если sin α = 3/5

Answer 1

sinα = 3/5;

cosα = √(1 - sin²α)

cosα = √(1 - 9/25) = √(16/25) = 4/5

tgα = sinα/cosα = (3/5)/(4/5) = 3/4

ctgα = 1/tgα = 1/(3/4) = 4/3