Question

${x}^{2} - 10x + 4 = 0$
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Answer 1

Ответ:

5+$sqrt{21}$;  5-$sqrt{21}$

Объяснение:

D= b^2-4ac = 100 - 16 = 84

$sqrt{D}= sqrt{84}$ = $2sqrt{21}$

x1 = (-b+$sqrt{D}$)/2a = (10+2$sqrt{21}$)/2 = 5+$sqrt{21}$

x2 = (-b-$sqrt{D}$)/2a = (10-2$sqrt{21}$)/2 = 5-$sqrt{21}$