Question

ПОМОГИТЕ С АЛГЕБРОЙ ПОЖАЛУЙСТА

Answer 1

Ответ:

1)1-t^2+2tc-c^2=(1-t+c)×(1+t-c)

2)2u^4y^2+16uy^5= 2uy^2×(u+2y)×(u^2-2uy+4y^2)

Answer 2

Ответ:

• $(1 - t + c)(1 + t - c) :$
• $2u {y}^{2} ( u + 2y)( {u}^{2} - 2uy + 4 {y}^{2} ) :$

Объяснение:

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$1 - {t}^{2} + 2tc - {c}^{2} = 1 - ({t}^{2} - 2tc + {c}^{2}) = 1 - {(t - c)}^{2} = (1 - t + c)(1 + t - c)$

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$2 {u}^{4} {y}^{2} + 16u {y}^{5} = 2u {y}^{2} ( {u}^{3} + 8 {y}^{3} ) = 2u {y}^{2} ( u + 2y)( {u}^{2} - 2uy + 4 {y}^{2} )$