Question

Решите пожалуйста интеграл

Answer 1

$displaystyleintlimits^0_{-3}frac{3dx}{sqrt{25+5x}}=frac{3}{sqrt{5}}intlimits^0_{-3}frac{d(5+x)}{sqrt{5+x}}=frac{6}{sqrt5}sqrt{5+x}|^0_{-3}=\=frac{6}{sqrt5}(sqrt5-sqrt2)=6-6sqrtfrac{2}{5}$