Question

помогите пж с алгебру буду сильно сильно благодарен

Answer 1

1.

$frac{1}{3}sqrt{28} =sqrt{frac{1}{9}cdot 28 }=sqrt{frac{28}{9} }$

2.

$sqrt{36cdot 5}=sqrt{36}cdot sqrt{5}=6sqrt{5}$

3.

$1 < 49 < 121< 271Rightarrow sqrt{1} <sqrt{49} <sqrt{121} <sqrt{271}$

4.

$(sqrt{10}+sqrt{7})^2=(sqrt{10})^2+2sqrt{10} cdot sqrt{7}+(sqrt{7})^2=10+2sqrt{70}+7=17+2sqrt{70}$

5.

$A=8cdotsqrt{45}=8cdotsqrt{9cdot 5}=8cdotsqrt{9}cdot sqrt{5}=8cdot3cdotsqrt{5}=24cdot sqrt{5}$

$B=10cdotsqrt{54}=10cdotsqrt{9cdot 6}=10cdotsqrt{9}cdot sqrt{6}=10cdot3cdotsqrt{6}=30cdot sqrt{6}$

$A < B$