Question

frac{3(x^{2}-11) }{5} - frac{2(x^{2}-60) }{7} =36

Answer 1

Ответ:

Объяснение:

$frac{3(x^{2}-11) }{5} - frac{2(x^{2}-60) }{7} =36$

$frac{3x^2-33}{5} -frac{2x^2-120}{7} -frac{36}{1} =0$

$frac{21x^2-231-10x^2+600-1260}{35}=0\ 11x^2-891=0\11x^2=891\x^2=891:11\x^2=81\x_1=9\x_2=-9$

Answer 2

$displaystyle tt frac{3cdot(x^2-11)}{5}-frac{2cdot(x^2-60)}{7}=36\\ displaystyle tt frac{3cdot(x^2-11)}{5}-frac{2cdot(x^2-60)}{7}-36=0\\displaystyle tt frac{21cdot(x^2-11)-10cdot(x^2-60)-1260}{35}=0\\ displaystyle tt 21x^2-231-10x^2+600-1260=0\displaystyle tt 11x^2-891=0\displaystyle tt 11x^2=891\displaystyle tt x^2=891div11\displaystyle tt x^2=81\displaystyle tt x=бsqrt{81}\displaystyle tt bold{x_1=9}\displaystyle tt bold{x_2=-9}$