Question

решите квадратные уравнение неполным способом
1-9х^2=0
2x^2-2x=0

Answer 1

Ответ:

$1-9x^{2} =0\-9x^{2} =-1\x^{2} =frac{1}{9}$⇒  $x=+-frac{1}{3}$

x=-1/3

x=1/3

$2x^{2} -2x=0\2x(x-1)=0\x(x-1)=0\x=0\x-1=0$⇒$x=1$

x=0

x=1

Answer 2

1)

$displaystyle tt 1-9x^2=0\\displaystyle tt 1=9x^2\\ displaystyle tt 9x^2=1\\ displaystyle tt x^2=frac{1}{9}\\ displaystyle tt x=бsqrt{frac{1}{9}}\\ displaystyle tt bold{x_1=frac{1}{3}}\\ displaystyle tt bold{x_2=-frac{1}{3}}$

2)

$displaystyle tt 2x^2-2x=0\displaystyle tt 2x(x-1)=0\\displaystyle tt x(x-1)=0\ displaystyle tt bold{x_1=0}\\displaystyle tt x-1=0\displaystyle tt bold{x_2=1}$