Question

СРОЧНО
y^2+1,4y+0,49−4y^2=0
Заранее огромное спасибо♥️

Answer 1

$displaystyle tt y^2+1,4y+0,49-4y^2=0\displaystyle tt -3y^2+1,4y+0,49=0 : : : : : | cdot(-100)\displaystyle tt 300y^2-140y-49=0\displaystyle tt 300y^2-210y+70y-49=0\displaystyle tt 30y(10y-7)+7(10y-7)=0\displaystyle tt (10y-7)(30y+7)=0\\ displaystyle tt 10y-7=0\displaystyle tt 10y=7\displaystyle tt y=7div10\displaystyle tt bold{y_1=0,7}\\ displaystyle tt 30y+7=0\displaystyle tt 30y=-7\displaystyle tt bold{y_2=-frac{7}{30}}$