Question

Помогите пожалуйста решить задачи по физике

Answer 1

Ответ:

Объяснение:

#1

$n = dfrac{c}{v} = dfrac{3*10^8}{2.5*10^8} = 1.2$

#2

$n = dfrac{sinalpha}{sinbeta} = dfrac{sin60^circ}{sin30^circ} = sqrt{3}$

#3

$n = dfrac{sinalpha}{sinbeta} to sinbeta = dfrac{sinalpha}{n} = dfrac{sin60^circ}{2.5} = dfrac{sqrt{3}}{5} to beta approx 20.27^circ$

#4

$n = dfrac{c}{v}\n = dfrac{sinalpha}{sinbeta} to sinbeta = dfrac{sinalpha}{n} = dfrac{v*sinalpha}{c} = dfrac{1.5*10^8*sin45^circ}{3*10^8} = dfrac{sqrt{2}}{4} to beta approx 20.72^circ$

Answer 2

спасибо!!))