Question

решите уравнения: sin(x3+п3)=-1

Answer 1

$sin(3x+3pi )=-1\3x+3pi =frac{3pi }{2} +2pi n$ , $n$ ∈ Ζ

$3x=-frac{3pi }{2} +2pi n$ , $n$ ∈ Ζ

$x = -frac{pi }{2} +frac{2pi n }{3}$ , $n$ ∈ Ζ