Question

sin x (2x-п/4) = - корень3/2

Answer 1

$sin(2x-frac{pi}{4})=-frac{sqrt{3}}{2}$
$2x-frac{pi}{4}=(-1)^k*arcsin(-frac{sqrt{3}}{2})+pi*k$
$2x-frac{pi}{4}=(-1)^k*(-frac{pi}{3})+pi*k$
$2x=frac{pi}{4}+(-1)^{k+1}*frac{pi}{3}+pi*k$
$x=frac{pi}{8}+(-1)^{k+1}*frac{pi}{6}+frac{pi*k}{2}$

k  є Z