Question

2x^2+xКорень5-15=0



(Между x и 5 корень)

Answer 1

Ответ:

$2x^2 + xsqrt{5} - 15 = 0\\D = 5 + 120 = 125\\sqrt D = 5sqrt{5}\\ x_1=frac{-sqrt{5}-5sqrt 5}{4} = -frac{6sqrt 5}{4} = -1,5sqrt 5\\x_2=frac{-sqrt{5}+5sqrt 5}{4} = frac{4sqrt 5}{4} = sqrt 5$