Question

Это будет чудо человек если решит такое! Прошу найдись пожалуйста человечек!!!

Answer 1

Ответ:

1.х=1

2.х=-12

3.х=3

4.х=-11

5.х=-10,5

6.х=6

7.х=0,1

8.х=7

9.х=4,4

10.х=73,25

Answer 2

Прошу.. если не сложно, можно с решением?

Answer 3

Ответ:

1)

$log_{2}(7 + x) = 3 \ {2}^{3} = 7 + x \ 8 = 7 + x \ x = 1$

2)

$log_{2}(15 + x) = log_{2}3 \ 15 + x = 3 \ x = - 12$

3)

$log_{4}(x + 8) = log_{4}(5x - 4) \ x + 8 = 5x - 4 \ - 4x = - 12 \ x = 3$

4)

$log_{ frac{1}{4} }(9 - 5x) = - 3 \ ({ frac{1}{4} })^{ - 3} = 9 - 5x \ 64 = 9 - 5x \ 5x = - 55 \ x = - 11$

5)

$log_{2}(18 - 6x) = 4 log_{2}3 \ 18 - 6x = {3}^{4} \ 18 - 6x = 81 \ - 6x = 63 \ x = - 10.5$

6)

$log_{4}( {x}^{2} + x) = log_{4}( {x}^{2} + 6) \ {x}^{2} + x = {x}^{2} + 6 \ x = 6$

7)

$log_{2}(5 + 2x) = log_{2}(1 - 2x) + 2 \ log_{2}(5 + 2x) = log_{2}(1 - 2x) + log_{2}4 \ log_{2}(5 + 2x) = log_{2}(4 - 8x) \ 5 + 2x = 4 - 8x \ 10x = - 1 \ x = - 0.1$

8)

$log_{x - 4}27 = 3 \ {(x - 4)}^{3} = 27 \ x = 7$

9)

$log_{16} {2}^{5x - 6} = 4 \ {16}^{4} = {2}^{5x - 6} \ {2}^{8} = {2}^{5x - 6} \ 8 = 5x - 6 \ 5x = 14 \ x = 2.8$

10)

${2}^{ log_{8}(4x + 50) } = 7 \ {2}^{ frac{1}{3} log_{2}(4x + 50) } = 7 \ {2}^{ log_{2} {(4x + 50)}^{ frac{1}{3} } } = 7 \ {(4x + 50)}^{ frac{1}{3} } = 7 \ 4x + 50 = {7}^{3} \ 4x + 50 = 343 \ 4x = 293 \ x = 73.25$