Question

2 cos (4x + П/3)+корень с 3=0 помогите с уравнением

Answer 1

2 cos (4x+ π/3)+√3=0

cos (4x+ π/3)=-√3/2

4x+ π/3=±arccos(-√3/2)+2πn; n∈ Z

4x+ π/3=±(π-arccos(√3/2)+2πn; n∈ Z

4x+ π/3=±(π-π/6)+2πn n∈ Z

4x+ π/3=±(5π/6)+2πn; n∈ Z

4x=- π/3±(5π/6)+2πn; n∈ Z

x=- π/12±5π/24+0.5πn; n∈ Z