Question

Будь ласка зробіть 8)
Благаю

Answer 1

$left(3x-1right)left(3x+1right)-left(x-4right)left(x-2right)=0\9x^2-1-(x^2-6x+8) = 0\9x^2-1-x^2+6x-8 = 0\8x^2+6x-9 = 0\D=6^2-4cdot 8cdot (-9) = 36+288 = 324 = 18^2\x_1=frac{-6+sqrt{D}}{2cdot 8} = frac{-6+18}{16}= frac{12}{16}=frac{3}{4} =0,75 \x_2=frac{-6-sqrt{D}}{2cdot 8} = frac{-6-18}{16}= -frac{24}{16}=-frac{3}{2} = -1,5$