Question

Пожалуйста помогите!!! 60 баллов!!! (1 Задание, с решением)

Answer 1

$frac{ {x}^{2} }{ {(2x + 3)}^{2} } - frac{3x}{2x + 3} + 2 = 0, : 2x + 3≠0 \ frac{ {x}^{2} }{ {(2x + 3)}^{2} } - frac{3x(2x + 3)}{ {(2x + 3)}^{2} } + frac{2(2x +3 ) ^{2} }{ {(2x + 3)}^{2} } = 0 \ {x}^{2} - 6 {x}^{2} - 9x + 2(4 {x}^{2} + 12x + 9) = 0 \ - 5 {x}^{2} - 9x + 8 {x}^{2} + 24x + 18 = 0 \ 3 {x}^{2} + 15x + 18 = 0 \ {x}^{2} + 5x + 6 = 0, : x≠ - 1.5 \ D = {5}^{2} - 4 times 6 = 1 \ x_{1} = frac{ - 5 + 1}{2} = - 2 \ x_{2} = frac{ - 5 - 1}{2} = - 3$

Ответ: -3, -2.