Question

Даю 100 баллов срочно решите плиз

Answer 1

$1); ; 6x^3-24x=0; ; ,; ; 6xcdot (x^2-4)=0; ,\\6xcdot (x-2)(x+2)=0\\x_1=0\\x-2=0; ; ,; ; x_2=2\\x=2=0; ; ,; ; x_3=-2\\Otvet:; ; 0; ;; 2; ;; -2; .$

$2); ; 25x^3-10x^2+x=0; ; ,; ; xcdot (25x^2-10x+1)=0; ,\\xcdot (5x-1)^2=0\\x_1=0\\5x-1=0; ; ,; ; x_2=frac{1}{5}\\Otvet:; ; 0; ;; frac{1}{5}; .$

Answer 2

$6 {x}^{3} - 24x = 0 \ 6x( {x}^{2} - 4) = 0 \ x = 0 \ {x}^{2} = 4 \ x_{1} = 0 \ x_{2/3} =±2$

Ответ: -2, 0, 2

$25 {x}^{3} - 10 {x}^{2} + x = 0 \ x(25 {x}^{2} - 10x + 1) = 0 \ x_{1} = 0 \ (5x)^{2} - 2 times 5x + 1 = 0 \ (5x - 1)^{2} = 0 \ 5x - 1 = 0 \ 5x = 1 \ x _{2}= 0.2$

Ответ: 0, 0.2