Question

Рівняння8,73/x=45;6y+3,4=38,8

Answer 1

1) $frac{8,73}{x} =45\frac{frac{873}{100} }{x} =45\frac{873}{100x} =45\873=4500x\4500x=873\x=frac{97}{500} \x=0,194$

2) $6y+3,4=38,8\6y=38,8-3,4\6y=35,4\y=5,9$